100 Most Expected Percentage Questions for AFCAT 2026 with Answers & Shortcut Tricks

Percentage Questions for AFCAT 2026

Preparing for AFCAT 2026? Percentage is one of the most important topics in the Quantitative Aptitude section. Questions from Percentage are frequently asked directly and also form the foundation for topics like Profit & Loss, Simple Interest & Compound Interest, Ratio & Proportion, and Data Interpretation.

If your Percentage concepts are strong, you'll be able to solve many arithmetic questions much faster during the exam.

Before moving to advanced arithmetic, you can also practice these topics:

These articles cover the concepts that are closely connected with Percentage and will strengthen your overall Quant preparation.

Important Percentage Formulas

Percentage Formula = Percentage = (Value ÷ Total Value) × 100
Increase Formula = Percentage Increase = (Increase ÷ Original Value) × 100
Decrease Formula = Percentage Decrease = (Decrease ÷ Original Value) × 100

Convert Percentage into Fraction

Percentage	Fraction
10%	1/10
12.5%	1/8
20%	1/5
25%	1/4
40%	2/5
50%	1/2
60%	3/5
75%	3/4
80%	4/5

AFCAT Percentage Shortcut Tricks

Trick 1

50% means Half
25% means One-Fourth
20% means One-Fifth
10% means One-Tenth

Trick 2

To calculate 15% of a number = 10% + 5%
Example: 15% of 400 = 40 + 20 = 60

Trick 3

To calculate 35% = 30% + 5%

This method saves a lot of calculation time in the exam.

What is 25% of 480?

A. 100
B. 110
C. 120
D. 130

Solution

25% = 1/4
480 ÷ 4 = 120

Shortcut

25% always means divide by 4.

40% of a number is 96. Find the number.

A. 200
B. 220
C. 240
D. 250

Solution

40% = 96
100% = (96 × 100) ÷ 40 = 240

Shortcut

Number = (Given Value × 100) ÷ Percentage

What percentage of 250 is 50?

A. 15%
B. 18%
C. 20%
D. 25%

Solution

Percentage = (50 ÷ 250) × 100 = 20%

A student's marks increase from 320 to 400. Find the percentage increase.

A. 20%
B. 22%
C. 25%
D. 30%

Solution

Increase = 400 − 320 = 80
Percentage Increase = (80 ÷ 320) × 100 = 25%

A shirt priced at ₹2,000 is sold after a 15% discount. Find the selling price.

A. ₹1,600
B. ₹1,650
C. ₹1,700
D. ₹1,750

Solution

Discount = 15% of 2,000 = ₹300
Selling Price = 2,000 − 300 = ₹1,700

Questions on Discount are directly connected with Profit & Loss. Once you complete this Percentage series, your next topic should be Profit & Loss.

35% of a number is 140. Find the number.

A. 350
B. 380
C. 400
D. 420

Solution

Number = (140 × 100) ÷ 35 = 400

What is 12.5% of 640?

A. 60
B. 70
C. 80
D. 90

Solution

12.5% = 1/8
640 ÷ 8 = 80

Shortcut

Remember: 12.5% = 1/8

The population of a town increases from 40,000 to 46,000. Find the percentage increase.

A. 10%
B. 12%
C. 15%
D. 18%

Solution

Increase = 6,000
Percentage Increase = (6,000 ÷ 40,000) × 100 = 15%

A number is decreased by 20% and becomes 320. Find the original number.

A. 360
B. 380
C. 400
D. 420

Solution

80% = 320
100% = (320 × 100) ÷ 80 = 400

If 60% of a number is 180, find 35% of that number.

A. 95
B. 100
C. 105
D. 110

Solution

Number = (180 × 100) ÷ 60 = 300
35% of 300 = 105

Common Fraction to Percentage Conversion

Fraction	Percentage
1/2	50%
1/3	33.33%
1/4	25%
1/5	20%
2/5	40%
3/5	60%
4/5	80%
5/8	62.5%

Remembering these conversions can save 20–30 seconds per question.

A student's marks increase from 480 to 576. Find the percentage increase.

A. 18%
B. 20%
C. 22%
D. 25%

Solution

Increase = 576 − 480 = 96
Percentage Increase = (96 ÷ 480) × 100 = 20%

Shortcut

Increase ÷ Original × 100

The price of a laptop is reduced by 15%. If the original price was ₹60,000, find the new price.

A. ₹49,000
B. ₹50,000
C. ₹51,000
D. ₹52,000

Solution

15% of ₹60,000 = ₹9,000
New Price = 60,000 − 9,000 = ₹51,000

A number is increased by 25% and becomes 500. Find the original number.

A. 360
B. 380
C. 400
D. 420

Solution

125% = 500
100% = (500 × 100) ÷ 125 = 400

Shortcut

Original Value = New Value × 100 ÷ (100 + Increase%)

A shopkeeper gives a 20% discount on an item marked at ₹2,500. Find the selling price.

A. ₹1,900
B. ₹2,000
C. ₹2,100
D. ₹2,200

Solution

Discount = 20% of ₹2,500 = ₹500
Selling Price = ₹2,500 − ₹500 = ₹2,000

The population of a village decreases from 25,000 to 22,500. Find the percentage decrease.

A. 8%
B. 10%
C. 12%
D. 15%

Solution

Decrease = 2,500
Percentage Decrease = (2,500 ÷ 25,000) × 100 = 10%

Whenever the question says "decreased to" or "increased to", always divide by the original value, not the final value.

A salary increases by 20% in the first year and 10% in the second year. Find the overall percentage increase.

A. 28%
B. 30%
C. 32%
D. 35%

Solution

Net % Change = A + B + (A × B)/100 = 20 + 10 + (20 × 10)/100 = 20 + 10 + 2 = 32%

Shortcut

x% followed by y%
Net Increase = x + y + (xy/100)

The value of a machine decreases by 10% every year. If its present value is ₹81,000, what was its value 2 years ago?

A. ₹90,000
B. ₹95,000
C. ₹1,00,000
D. ₹1,05,000

Solution

After 2 years: Value = Original × (90/100)²
81,000 = Original × 0.81
Original = 81,000 ÷ 0.81 = ₹1,00,000

If 35% of a number equals 140, what is 65% of the same number?

A. 240
B. 250
C. 260
D. 270

Solution

35% = 140
100% = (140 × 100) ÷ 35 = 400
65% of 400 = 260

The price of sugar increases by 25%. By what percentage should consumption be reduced so that expenditure remains unchanged?

A. 15%
B. 18%
C. 20%
D. 25%

Solution

Required Reduction = Increase ÷ (100 + Increase) × 100 = 25 ÷ 125 × 100 = 20%

Shortcut Formula

If price increases by x%
Reduction = x/(100+x) ×100

The price of petrol decreases by 20%. A person increases consumption by 25%. Find the net effect on expenditure.

A. 2% Increase
B. No Change
C. 4% Decrease
D. 5% Increase

Solution

Take original expenditure = 100
Price becomes = 80
Consumption becomes = 125
New Expenditure
= (80 × 125) ÷ 100 = 100
Hence, No Change

Shortcut

Net Change = A + B + (AB/100)
For one increase and one decrease, use signs carefully: = (+25) + (−20) + (25 × −20)/100 = 25 − 20 − 5 = 0%

The salary of an employee increases by 15% every year. If his current salary is ₹52,900, what was his salary one year ago?

A. ₹44,000
B. ₹45,000
C. ₹46,000
D. ₹47,000

Solution

Current Salary = Previous × 115%
Previous = 52,900 × 100 ÷ 115 = ₹46,000

The population of a city decreases by 10% in the first year and 20% in the second year. Find the total percentage decrease.

A. 28%
B. 30%
C. 32%
D. 35%

Solution

Net Change = (−10) + (−20) + (−10 × −20)/100 = −10 −20 +2 = −28%

A student scores 72% marks in an exam and gets 432 marks. Find the maximum marks.

A. 500
B. 550
C. 600
D. 650

Solution

72% = 432
100% = (432 ×100) ÷72 = 600

The ratio of boys and girls in a class is 3 : 5. Find the percentage of girls.

A. 35%
B. 50%
C. 62.5%
D. 75%

Solution

Girls = 5 Parts
Total = 8 Parts
Percentage = (5 ÷8) ×100 = 62.5%

Many Percentage questions are solved much faster by first converting them into a ratio.

The price of an article increases by 40%. By what percentage should consumption decrease so that expenditure remains unchanged?

A. 25%
B. 28.57%
C. 30%
D. 35%

Solution

Reduction = Increase ÷ (100 + Increase) = 40 ÷140 ×100 = 28.57%

A number is first increased by 30% and then decreased by 30%. Find the net percentage change.

A. No Change
B. 9% Increase
C. 9% Decrease
D. 6% Decrease

Solution

Net Change = 30 −30 +(30×−30)/100 = −9%

If 18% of a number is 90, what is 42% of that number?

A. 180
B. 200
C. 210
D. 225

Solution

18% =90
100% =500
42% =210

A shopkeeper purchases an article for ₹800 and sells it at a profit of 25%. Find the selling price.

A. ₹900
B. ₹950
C. ₹1,000
D. ₹1,050

Solution

Profit =25% of800 =₹200
Selling Price =₹1,000

A number is decreased by 35% and becomes 520. Find the original number.

A. 700
B. 760
C. 800
D. 850

Solution

65% =520
100% =(520×100)÷65 =800

In a school, 45% of students are girls. If there are 990 boys, find the total number of students.

A. 1,700
B. 1,750
C. 1,800
D. 1,900

Solution

Boys =55%
55%=990
100%=1800

The marked price of an article is ₹2,400. A discount of 25% is offered. Find the discount amount.

A. ₹500
B. ₹550
C. ₹600
D. ₹650

A company increases salaries by 12%. If an employee's new salary is ₹56,000, find the old salary.

A. ₹48,000
B. ₹49,000
C. ₹50,000
D. ₹52,000

Solution

Old Salary =56,000×100÷112 =₹50,000

What percentage of 640 is 96?

A. 12%
B. 15%
C. 18%
D. 20%

The value of an investment becomes ₹13,200 after increasing by 10%. Find the original investment.

A. ₹11,000
B. ₹12,000
C. ₹12,500
D. ₹13,000

If 80% of a number is 160, then 15% of the same number equals

A. 25
B. 30
C. 35
D. 40

The price of petrol decreases by 25%. A person increases consumption by 20%. Find the net effect on expenditure.

A. 10% Decrease
B. 8% Decrease
C. 5% Decrease
D. No Change

Solution

Net Change =20−25+(20×−25)/100 =−10%

An item costing ₹1,500 is sold for ₹1,800. Find the profit percentage.

A. 18%
B. 20%
C. 22%
D. 25%

The ratio of passed to failed students is 9 : 1. Find the percentage of students who passed.

A. 80%
B. 85%
C. 90%
D. 95%

A number is increased by 20% and then by another 25%. Find the overall percentage increase.

A. 40%
B. 45%
C. 50%
D. 55%

Solution

Net Increase =20+25+(20×25)/100 =20+25+5 =50%

A student's marks increase from 640 to 800. Find the percentage increase.

A. 20%
B. 22%
C. 25%
D. 30%

Solution

Increase = 800 − 640 = 160
Percentage Increase = (160 ÷ 640) × 100 = 25%

An item's price is reduced by 12%. If the original price was ₹4,500, find the new price.

A. ₹3,900
B. ₹3,960
C. ₹4,000
D. ₹4,050

Solution

12% of ₹4,500 = ₹540
New Price = ₹4,500 − ₹540 = ₹3,960

If 18% of a number is 126, find 65% of that number.

A. 420
B. 440
C. 455
D. 465

Solution

18% = 126
100% = (126 × 100) ÷ 18 = 700
65% = 455

A salary is increased by 30% and later reduced by 20%. Find the net percentage change.

A. 2% Increase
B. 4% Increase
C. 5% Increase
D. No Change

Solution

Net Change = 30 − 20 + (30 × -20)/100 = 30 − 20 − 6 = 4% Increase

Shortcut

Use: A + B + (AB/100)

(Remember to use a negative sign for decreases.)

A number is first decreased by 40% and then increased by 25%. Find the net percentage change.

A. 20% Decrease
B. 25% Decrease
C. 15% Decrease
D. 10% Decrease

Solution

Net Change = -40 + 25 + (-40 × 25)/100 = -40 + 25 -10 = -25%

A 20% increase followed by a 20% decrease is not zero.
Net Change = +20 −20 −4 = 4% Decrease

This is a very common AFCAT trap.

The population of a town increases by 15% every year. If the present population is 52,900, what was the population one year ago?

A. 44,000
B. 45,000
C. 46,000
D. 47,000

Solution

Previous Population = 52,900 ×100 ÷115 = 46,000

The marked price of an article is ₹8,000. A discount of 12.5% is offered. Find the selling price.

A. ₹6,800
B. ₹7,000
C. ₹7,200
D. ₹7,400

Solution

12.5% = 1/8
Discount = 8,000 ÷8 = ₹1,000
Selling Price = ₹7,000

A student scores 468 marks, which is 78% of the total marks. Find the maximum marks.

A. 550
B. 580
C. 600
D. 650

The ratio of boys to girls is 9 : 11. Find the percentage of boys.

A. 40%
B. 42%
C. 45%
D. 48%

Solution

Boys = 9/20 ×100 = 45%

A machine depreciates by 20% every year. If its present value is ₹51,200, find its value 2 years ago.

A. ₹75,000
B. ₹80,000
C. ₹82,000
D. ₹85,000

Solution

Present = Original × (80/100)²
51,200 = Original ×0.64
Original = ₹80,000

What percentage of 960 is 144?

A. 12%
B. 15%
C. 18%
D. 20%

A number increases from 250 to 325. Find the percentage increase.

A. 25%
B. 28%
C. 30%
D. 32%

The price of sugar increases by 20%. By what percentage should consumption be reduced to keep expenditure unchanged?

A. 15%
B. 16⅔%
C. 18%
D. 20%

Shortcut

Reduction =20÷120×100 =16⅔%

A person earns ₹72,000 annually. He saves 25% of his income. Find his annual expenditure.

A. ₹52,000
B. ₹54,000
C. ₹56,000
D. ₹58,000

If 35% of a number equals 280, find 15% of that number.

A. 100
B. 110
C. 120
D. 130

The value of an investment increases by 10%, then by 20%. Find the overall increase.

A. 28%
B. 30%
C. 32%
D. 35%

A trader buys an article for ₹2,400 and sells it for ₹3,000. Find the profit percentage.

A. 20%
B. 22%
C. 25%
D. 30%

A class has 40 students. If 60% are girls, find the number of boys.

A. 14
B. 15
C. 16
D. 18

A number is reduced by 25% and becomes 540. Find the original number.

A. 700
B. 710
C. 720
D. 740

A student's marks are increased by 20% and then by another 10%. If the original marks were 500, find the final marks.

A.640
B. 650
C. 660
D. 670

Solution

500 ×1.20 ×1.10 =500 ×1.32 = 660

A number increases from 480 to 600. Find the percentage increase.

A. 20%
B. 22%
C. 25%
D. 30%

Solution

Increase = 600 − 480 = 120
Percentage Increase = (120 ÷ 480) × 100= 25%

A shirt marked at ₹2,800 is sold after a 15% discount. Find the selling price.

A. ₹2,320
B. ₹2,360
C. ₹2,380
D. ₹2,400

If 32% of a number is 256, find 75% of that number.

A. 540
B. 560
C. 580
D. 600

The population of a village decreases by 15% every year. If the current population is 7,225, what was the population one year ago?

A. 8,000
B. 8,250
C. 8,500
D. 9,000

A student's marks increase by 25% and become 500. Find the original marks.

A. 360
B. 380
C. 400
D. 420

Whenever the question asks for the original value after an increase, Use: Original = Final ×100 ÷ (100 + Increase%)

The price of sugar increases by 30%. By what percentage should consumption decrease so that expenditure remains unchanged?

A. 20%
B. 22%
C. 23.08%
D. 25%

A trader earns a 20% profit by selling an article for ₹2,400. Find the cost price.

A. ₹1,800
B. ₹2,000
C. ₹2,100
D. ₹2,200

If 84% of a number equals 336, find 35% of that number.

A. 130
B. 135
C. 140
D. 145

The ratio of boys to girls is 7 : 13. Find the percentage of girls.

A. 60%
B. 62%
C. 65%
D. 70%

A number is first increased by 40% and then decreased by 25%. Find the net percentage change.

A. 5% Increase
B. 5% Decrease
C. No Change
D. 10% Increase

The value of a machine depreciates by 20% every year. If its current value is ₹64,000, find its value one year ago.

A. ₹75,000
B. ₹80,000
C. ₹82,000
D. ₹85,000

A student secures 540 marks, which is 90% of the total marks. Find the maximum marks.

A. 580
B. 590
C. 600
D. 620

The marked price of a TV is ₹48,000. A discount of 12.5% is offered. Find the selling price.

A. ₹40,000
B. ₹41,000
C. ₹42,000
D. ₹43,000

What percentage of 720 is 180?

A. 20%
B. 22%
C. 25%
D. 30%

An employee spends 80% of his salary. If he saves ₹12,000, find his monthly salary.

A. ₹50,000
B. ₹55,000
C. ₹60,000
D. ₹65,000

The price of petrol decreases by 10% while consumption increases by 20%. Find the net effect on expenditure.

A. 6% Increase
B. 8% Increase
C. 10% Increase
D. 12% Increase

A number decreases from 840 to 672. Find the percentage decrease.

A. 18%
B. 20%
C. 22%
D. 25%

If 45% of a number is 225, then 28% of the same number equals

A. 130
B. 135
C. 140
D. 145

The population of a town increases by 10% every year. If the current population is 1,21,000, what was the population one year ago?

A. 1,00,000
B. 1,05,000
C. 1,10,000
D. 1,15,000

The cost price of an article is ₹1,600. It is sold at a profit of 15%. Find the selling price.

A. ₹1,780
B. ₹1,820
C. ₹1,840
D. ₹1,860

Percentage = (Value ÷ Total) × 100

Increase% = (Increase ÷ Original) ×100

Decrease% = (Decrease ÷ Original) ×100

Net Change= A + B + (AB/100)

(Use a negative sign for decreases.)

Original= Final ×100 ÷ (100 ± Percentage)

Required Reduction= Increase ÷ (100 + Increase)×100

The salary of an employee is increased by 25% and then by another 20%. If the original salary was ₹40,000, find the final salary.

A. ₹58,000
B. ₹60,000
C. ₹62,000
D. ₹64,000

Solution

Final Salary = 40,000 × 125% × 120% = 40,000 × 1.25 × 1.20 = ₹60,000

Shortcut

Net Increase = 25 + 20 + (25×20)/100 = 50%

The price of rice increases by 20%. By what percentage should consumption decrease so that total expenditure remains unchanged?

A. 15%
B. 16⅔%
C. 18%
D. 20%

Solution

Required Reduction = Increase ÷ (100 + Increase) ×100 = 20 ÷120 ×100 = 16⅔%

A student secures 504 marks, which is 84% of the maximum marks. Find the maximum marks.

A. 560
B. 580
C. 600
D. 620

Solution

Maximum Marks = (504 ×100) ÷84 = 600

The ratio of boys and girls is 9 : 16. Find the percentage of girls.

A. 60%
B. 62%
C. 64%
D. 66%

Solution

Girls =16 Parts
Total =25 Parts
Percentage =(16÷25)×100 = 64%

A machine depreciates by 15% every year. If its present value is ₹72,250, what was its value one year ago?

A. ₹82,000
B. ₹84,000
C. ₹85,000
D. ₹86,000

Solution

Previous Value =72,250 ×100 ÷85 = ₹85,000

Whenever depreciation is given, Previous Value = Present ×100 ÷(100 − Depreciation%)

A trader purchases an article for ₹3,200 and sells it at a profit of 25%. Find the selling price.

A. ₹3,800
B. ₹4,000
C. ₹4,200
D. ₹4,400

Solution

Profit =25%
Selling Price =3200 ×125% = ₹4,000

If 45% of a number equals 360, find 15% of the same number.

A. 110
B. 115
C. 120
D. 125

Solution

45% =360
100% =800
15% =120

The population of a city increases by 10% every year. If the current population is 2,42,000, what was the population one year ago?

A. 2,10,000
B. 2,15,000
C. 2,20,000
D. 2,25,000

Solution

Previous Population =2,42,000 ×100 ÷110 = 2,20,000

An article is sold after giving a 20% discount on the marked price of ₹5,500. Find the selling price.

A. ₹4,200
B. ₹4,300
C. ₹4,400
D. ₹4,500

Solution

Discount =20%
Selling Price =80% of 5,500 = ₹4,400

The value of an investment increases by 20% in the first year and 25% in the second year. If the initial investment was ₹80,000, find the final amount.

A. ₹1,15,000
B. ₹1,18,000
C. ₹1,20,000
D. ₹1,25,000

Solution

Final Amount =80,000 ×120% ×125% =80,000 ×1.20 ×1.25 = ₹1,20,000

Shortcut

Net Increase =20 +25 +(20×25)/100 =50%
Final Amount =80,000 ×150% = ₹1,20,000

A person's salary increases by 10% every year. If his present salary is ₹72,600, what was his salary one year ago?

A. ₹64,000

B. ₹65,000

C. ₹66,000

D. ₹67,000

Solution

Previous Salary = 72,600 × 100 ÷ 110 = ₹66,000

The marked price of an article is ₹4,800. A shopkeeper offers a 25% discount. Find the selling price.

A. ₹3,400
B. ₹3,500
C. ₹3,600
D. ₹3,800

Solution

Selling Price = 75% of ₹4,800 = ₹3,600

A student scores 540 marks, which is 90% of the total marks. Find the maximum marks.

A. 580
B. 600
C. 620
D. 650

Solution

Total Marks = (540 × 100) ÷ 90 = 600

The ratio of boys to girls in a class is 8 : 12. Find the percentage of girls.

A. 50%
B. 55%
C. 60%
D. 65%

Solution

Girls = 12 Parts
Total = 20 Parts
Girls % = (12 ÷ 20) × 100 = 60%

The price of an article is increased by 25% and later decreased by 20%. Find the overall percentage change.

A. No Change
B. 2% Increase
C. 2% Decrease
D. 5% Increase

Solution

Net Change = +25 −20 +(25 × −20)/100 = 25 −20 −5 = 0%

Whenever one percentage increases and another decreases, Use: Net Change = A + B + (AB/100) (Remember to take decreases as negative.)

If 45% of a number equals 540, then 25% of that number is

A. 280
B. 290
C. 300
D. 320

Solution

45% = 540
100% = 1200
25% = 300

The value of a machine decreases by 20% every year. If its present value is ₹1,28,000, find its value one year ago.

A. ₹1,50,000
B. ₹1,60,000
C. ₹1,70,000
D. ₹1,80,000

Solution

Previous Value = 1,28,000 ×100 ÷80 = ₹1,60,000

The cost price of an article is ₹2,400. It is sold at a profit of 20%. Find the selling price.

A. ₹2,760
B. ₹2,800
C. ₹2,880
D. ₹3,000

Solution

Selling Price = 120% of ₹2,400 = ₹2,880

The population of a town increases by 25%. If the original population was 48,000, find the new population.

A. 56,000
B. 58,000
C. 60,000
D. 62,000

Solution

New Population = 48,000 ×125% = 60,000

A student's marks increase by 20% and then by another 15%. If the original marks were 500, find the final marks.

A. 680
B. 690
C. 700
D. 710

Solution

Final Marks = 500 ×120% ×115% = 500 ×1.20 ×1.15 = 500 ×1.38 = 690

Shortcut

Net Increase = 20 +15 +(20×15)/100 = 20 +15 +3 = 38%
Final Marks = 500 ×138% = 690