50 Most Expected Simple Interest & Compound Interest Questions for AFCAT 2026 with Shortcut Tricks
50 Most Expected SI & CI Questions with Shortcut Tricks
Important Formulas
Simple Interest
- SI = (Principal × Rate × Time) ÷ 100
- Amount = Principal + Simple Interest
Compound Interest
- Amount = Principal × (1 + Rate/100)^Time
- Compound Interest = Amount − Principal
AFCAT Shortcut Tricks
-
Trick 1 - Difference between two SI amounts
One Year Interest = Difference ÷ Difference in Years
Trick 2 - For 2 Years
CI − SI = Principal × Rate² ÷ 10000
Trick 3
- Money Doubles
- If money doubles in x years
- Then it becomes triple in 2x years (Simple Interest)
Multipliers to Remember
| Rate | 2 Years Multiplier |
|---|---|
| 5% | 1.1025 |
| 10% | 1.21 |
| 20% | 1.44 |
| 25% | 1.5625 |
| 50% | 2.25 |
Question 1
A sum of ₹8,000 is invested at 10% simple interest for 3 years. Find the interest earned.
- A. ₹2,000
- B. ₹2,200
- C. ₹2,400
- D. ₹2,600
Answer - C. ₹2,400
Solution: SI = (8000 ×10×3)/100 = ₹2,400
Shortcut
- 10% of ₹8,000 = ₹800
- 3 years = 800 ×3 = ₹2,400
Question 2
A person invested ₹12,000 at 8% simple interest for 5 years. Find the amount received.
- A. ₹16,200
- B. ₹16,800
- C. ₹17,000
- D. ₹17,400
Answer - B. ₹16,800
Solution: Interest =(12000×8×5)/100 =₹4,800
Amount: 12000+4800 =₹16,800
Shortcut
- 8% of ₹12,000 =₹960
- 5 years 960×5 =₹4,800
- Add Principal =₹16,800
Question 3
A sum becomes ₹15,600 in 4 years and ₹17,200 in 8 years at simple interest. Find the principal.
- A. ₹14,000
- B. ₹14,400
- C. ₹15,000
- D. ₹15,600
Answer - A. ₹14,000
Solution
- Difference: 17200−15600 =1600
- 4 years interest: 1600
- One year interest: 1600÷4 =400
- 4 years interest: 400×4 =1600
- Principal: 15600−1600 =₹14,000
Shortcut
- Difference ÷ Year Difference
- Always gives One Year Interest.
Question 4
A sum of ₹20,000 is invested at 12% simple interest. Find the interest after 5 years.
- A. ₹10,000
- B. ₹11,000
- C. ₹12,000
- D. ₹13,000
Answer - C. ₹12,000
Solution
- Interest =(20000×12×5)/100 =₹12,000
Shortcut
- 12×5=60% Interest =60% of ₹20,000 =₹12,000
Question 5
At what rate of simple interest will ₹10,000 earn ₹3,000 in 5 years?
- A. 4%
- B. 5%
- C. 6%
- D. 8%
Answer - C. 6%
Solution
- Rate =(3000×100)/(10000×5) =6%
Shortcut
- 3000 is 30% of 10000
- 30% in 5 years
- 30÷5 =6%
AFCAT Exam Tip (Questions 1–5)
Whenever you see:
- Difference between two amounts
- Amount after several years
- Interest for multiple years
First calculate the yearly interest.
- This reduces 70% of the calculation instantly.
Question 6
A sum becomes ₹24,200 in 2 years at 10% compound interest. Find the principal.
- A. ₹20,000
- B. ₹20,500
- C. ₹21,000
- D. ₹22,000
Answer - A. ₹20,000
Solution
- Multiplier for 10% (2 years) =1.21
- Principal: 24200÷1.21 =₹20,000
Shortcut
- Memorize: 10% for 2 years
- Multiplier = 1.21
Question 7
A sum of ₹15,000 is invested at 20% compound interest for 2 years. Find the amount.
- A. ₹20,600
- B. ₹21,000
- C. ₹21,600
- D. ₹22,000
Answer - C. ₹21,600
Solution
- Multiplier: 1.44
- Amount: 15000×1.44 =₹21,600
Shortcut
- 20% for 2 years
- Always multiply by 1.44
Question 8
Difference between SI and CI for 2 years at 10% is ₹120. Find the principal.
- A. ₹10,000
- B. ₹11,000
- C. ₹12,000
- D. ₹13,000
Answer - C. ₹12,000
Solution
- Formula: CI−SI =P×10²/10000
- 120=P×100/10000
- 120=P/100
- P=₹12,000
Shortcut
- For 2 years, directly use:
- Difference = P × R² ÷ 10000
Question 9
A sum doubles in 10 years at simple interest. In how many years will it become three times?
- A. 15
- B. 18
- C. 20
- D. 25
Answer - C. 20 years
Solution
Doubling means
- Interest=100%
- 10 years=100%
Triple means
- Interest=200%
- 200%=20 years
Shortcut
- Money doubles in x years ⇒ triples in 2x years (SI only).
Question 10
A sum becomes ₹9,680 in 2 years at 10% compound interest. Find the compound interest earned.
- A. ₹1,480
- B. ₹1,680
- C. ₹1,880
- D. ₹2,080
Answer - B. ₹1,680
Solution
- Principal: 9680÷1.21 =₹8,000
- Compound Interest: 9680−8000 =₹1,680
Shortcut
- First find the Principal using the multiplier, then subtract it from the Amount.
AFCAT Shortcut
- If the Rate and Time are known, don't always use the formula first.
- Think like this: Interest = Principal × Total Percentage
- This saves a lot of calculation.
Question 11
A sum of ₹25,000 is invested at 8% simple interest for 4 years. Find the amount.
- A. ₹32,000
- B. ₹33,000
- C. ₹34,000
- D. ₹35,000
Answer - B. ₹33,000
Solution
- Interest =(25000×8×4)/100 =₹8,000
- Amount: 25000+8000 =₹33,000
Shortcut
- 8×4=32%, 32% of ₹25,000 =₹8,000
Question 12
A sum amounts to ₹18,150 after 2 years at 10% compound interest. Find the principal.
- A. ₹15,000
- B. ₹15,500
- C. ₹16,000
- D. ₹16,500
Answer - A. ₹15,000
Solution
- Multiplier (10%, 2 years) =1.21
- Principal: 18150÷1.21 =₹15,000
Shortcut
- Whenever you see: 10%, 2 Years
- Immediately remember
- Multiplier =1.21
Question 13
The difference between SI and CI on a sum for 2 years at 20% is ₹400. Find the principal.
- A. ₹8,000
- B. ₹9,000
- C. ₹10,000
- D. ₹11,000
Answer: C. ₹10,000
Solution
- Difference =P×20²/10000
- 400=P×400/10000
- 400=P/25
- P=₹10,000
Shortcut
- At 20% Difference becomes Principal ×4%, 400 means 4% Therefore, Principal 400×25 =₹10,000
Question 14
A sum becomes ₹16,000 in 5 years and ₹18,000 in 10 years at simple interest. Find the principal.
- A. ₹14,000
- B. ₹13,500
- C. ₹12,000
- D. ₹15,000
Answer - A. ₹14,000
Solution
- Difference: 18000−16000 =₹2,000. This is 5 years interest.
- One year interest: 2000÷5 =₹400
- Interest for first 5 years: 400×5 =₹2,000
- Principal: 16000−2000 =₹14,000
Shortcut
- Difference ÷ Time Difference. Always gives 1 Year Interest
Question 15
At what rate of simple interest will ₹15,000 become ₹19,500 in 6 years?
- A. 4%
- B. 5%
- C. 6%
- D. 7%
Answer: B. 5%
Solution
- Interest: 19500−15000 =₹4,500
- Rate =(4500×100)/(15000×6) =5%
Shortcut
- Interest 4500 is 30%
- 30% in 6 years, 30÷6 =5%
AFCAT Smart Trick (Questions 11–15)
Whenever the principal and amount are given:
- Find Interest first.
- Convert Interest into Percentage.
- Divide by Years.
This avoids long formulas.
Question 16
A sum of ₹18,000 is invested at 20% compound interest for 2 years. Find the amount.
- A. ₹24,920
- B. ₹25,000
- C. ₹25,920
- D. ₹26,000
Answer - C. ₹25,920
Solution
- Multiplier 1.44
- Amount: 18000×1.44 =₹25,920
Shortcut
- 20%, 2 years Multiply directly by 1.44
Question 17
A sum doubles itself in 12 years at simple interest. How many years will it take to become 2.5 times?
- A. 16 years
- B. 18 years
- C. 20 years
- D. 24 years
Answer - B. 18 years
Solution
- Doubling means
- Interest 100%, 12 years. Therefore 1 year =8.33%
- To become 2.5 times
- Interest 150%, 150% takes 18 years
Shortcut
- Formula: Years Required =(Required Interest ÷100)×Doubling Time
- =(150÷100)×12
- =18 years
Question 18
A sum becomes ₹29,040 in 2 years at 10% compound interest. Find the compound interest earned.
- A. ₹4,840
- B. ₹5,040
- C. ₹5,240
- D. ₹5,440
Answer: B. ₹5,040
Solution
- Principal: 29040÷1.21 =₹24,000
- Compound Interest: 29040−24000 =₹5,040
Shortcut
- Always verify: CI = Amount − Principal
Question 19
The simple interest on a sum at 15% per annum for 4 years is ₹7,200. Find the principal.
- A. ₹10,000
- B. ₹11,000
- C. ₹12,000
- D. ₹12,500
Answer - C. ₹12,000
Solution
- SI =(P×15×4)/100
- 7200=P×60/100
- 7200=P×0.6
- P=₹12,000
Shortcut
- 15×4=60%
- Interest =60% of Principal, 7200÷0.6 =₹12,000
Question 20
A sum invested at 10% compound interest becomes ₹13,310 after 3 years. Find the principal.
- A. ₹9,000
- B. ₹10,000
- C. ₹11,000
- D. ₹12,000
Answer - B. ₹10,000
Solution
- For 10% and 3 years,
- Multiplier =1.331
- Principal: 13310÷1.331 =₹10,000
Shortcut
Remember these multipliers:
| Rate | 3 Years Multiplier |
|---|---|
| 10% | 1.331 |
| 20% | 1.728 |
| 5% | 1.157625 |
| 25% | 1.953125 |
AFCAT Magic Shortcut
If Principal Doubles in "x" Years
| Money Becomes | Required Time |
|---|---|
| 2 Times | x Years |
| 3 Times | 2x Years |
| 4 Times | 3x Years |
| 5 Times | 4x Years |
(Applicable only for Simple Interest)
Question 21
A sum becomes ₹21,600 in 3 years at 20% Compound Interest. Find the Principal.
- A. ₹12,000
- B. ₹12,500
- C. ₹13,000
- D. ₹15,000
Answer: B. ₹12,500
Solution
- Multiplier (20%, 3 years) = 1.20³ = 1.728
- Principal =21600÷1.728 =₹12,500
Shortcut
- Remember: 20% for 3 years = 1.728
Question 22
The Simple Interest on a sum is ₹5,400 for 6 years at 9% per annum. Find the Principal.
- A. ₹9,000
- B. ₹10,000
- C. ₹11,000
- D. ₹12,000
Answer: B. ₹10,000
Solution
- SI =(P×9×6)/100
- 5400=P×54/100
- 5400=P×0.54
- P=₹10,000
Shortcut
- 9×6 =54%
- Interest is 54%
- Principal: 5400÷0.54 =₹10,000
Question 23
A sum becomes ₹14,520 after 2 years at 10% Compound Interest. Find the Compound Interest.
- A. ₹2,320
- B. ₹2,420
- C. ₹2,520
- D. ₹2,620
Answer - B. ₹2,520
Solution
- Principal: 14520÷1.21 =₹12,000
- CI: 14520−12000 =₹2,520
Shortcut
- Always divide Amount by 1.21 first.
Question 24
A sum becomes ₹8,400 in 4 years and ₹9,600 in 8 years at Simple Interest. Find the Principal.
- A. ₹7,000
- B. ₹7,200
- C. ₹7,400
- D. ₹7,600
Answer: B. ₹7,200
Solution
- Difference: 9600−8400 =₹1200 4 years Interest
- One year Interest: 1200÷4 =₹300
- Interest for first 4 years: 300×4 =₹1200
- Principal: 8400−1200 =₹7200
Shortcut
- Difference ÷ Year Difference = One Year Interest
Question 25
At what rate of Simple Interest will ₹18,000 become ₹24,300 in 7 years?
- A. 4%
- B. 5%
- C. 6%
- D. 7%
Answer - B. 5%
Solution
- Interest: 24300−18000 =₹6,300
- Interest %6300÷18000×100=35%
- 35% for 7 years, 35÷7 =5%
Shortcut
- Interest % ÷ Years = Rate
AFCAT Shortcut (Questions 21–25)
Whenever Amount and Principal are given:
- Find Interest.
- Convert into Percentage.
- Divide by Time.
No lengthy formula needed.
Question 26
A sum of ₹30,000 is invested at 12% Compound Interest for 2 years. Find the Amount.
- A. ₹37,432
- B. ₹37,500
- C. ₹37,632
- D. ₹38,000
Answer: C. ₹37,632
Solution
- Multiplier 1.12² =1.2544
- Amount: 30000×1.2544 =₹37,632
Shortcut
- Remember: 12% for 2 years = 1.2544
Money doubles in 15 years at Simple Interest. How long will it take to become 4 times?
- A. 30 years
- B. 40 years
- C. 45 years
- D. 60 years
Answer: C. 45 years
Solution
- Double =100% Interest
- 15 years Four times =300% Interest
- 300% takes 45 years
Shortcut
- Four Times =3× Doubling Time, 15×3 =45
Question 28
Difference between SI and CI for 2 years at 15% is ₹270. Find the Principal.
- A. ₹10,000
- B. ₹11,000
- C. ₹12,000
- D. ₹13,000
Answer - C. ₹12,000
Solution
- Difference =P×15²/10000
- 270=P×225/10000
- P=270×10000÷225 =₹12,000
Shortcut
- For 2 years: CI − SI = P × R² / 10000
Question 29
A sum amounts to ₹10,648 after 2 years at 10% Compound Interest. Find the Principal.
- A. ₹8,600
- B. ₹8,700
- C. ₹8,800
- D. ₹8,900
- Principal: 10648÷1.21 =₹8,800
- Correct Answer: C. ₹8,800
Shortcut
- Whenever you see 10% for 2 years, divide by 1.21.
Question 30
A person borrowed ₹16,000 at 15% Simple Interest for 4 years. How much total Amount must he repay?
- A. ₹24,600
- B. ₹25,000
- C. ₹25,600
- D. ₹26,000
Answer - C. ₹25,600
Solution
- Interest =(16000×15×4)/100 =₹9,600
- Amount: 16000+9600 =₹25,600
Shortcut
- 15×4=60%
- Interest =60% of ₹16,000 =₹9,600
- Add Principal =₹25,600
AFCAT Smart Notes
| Rate | 2 Years | 3 Years |
|---|---|---|
| 5% | 1.1025 | 1.157625 |
| 10% | 1.21 | 1.331 |
| 12% | 1.2544 | 1.404928 |
| 15% | 1.3225 | 1.520875 |
| 20% | 1.44 | 1.728 |
| 25% | 1.5625 | 1.953125 |
Question 31
A sum amounts to ₹36,300 after 2 years at 10% Compound Interest. Find the Principal.
- A. ₹29,000
- B. ₹30,000
- C. ₹31,000
- D. ₹32,000
Correct Answer: B. ₹30,000
Solution
- Formula: Amount = Principal × (1.10)²
- Multiplier = 1.21
- Principal = 36,300 ÷ 1.21 = ₹30,000
Shortcut
For 10% CI (2 years)
- Always remember
- Multiplier = 1.21
- Just divide the Amount by 1.21.
- Time Required: 10–15 seconds
Question 32
The difference between Compound Interest and Simple Interest for 2 years at 12% per annum is ₹288. Find the Principal.
- A. ₹18,000
- B. ₹19,000
- C. ₹20,000
- D. ₹22,000
Correct Answer - C. ₹20,000
Solution
Formula
- Difference = Principal × Rate² ÷ 10000
- 288 = P × 144 ÷ 10000
- P = 288 × 10000 ÷ 144 = ₹20,000
Shortcut
- At 2 years Use only one formula:
- CI − SI = P × R² ÷ 10000
- No need to calculate SI and CI separately.
Question 33
A person invested ₹25,000 at 8% Simple Interest. After 6 years, he withdrew the entire amount. Find the total Amount.
- A. ₹36,000
- B. ₹37,000
- C. ₹38,000
- D. ₹39,000
Correct Answer - B. ₹37,000
Solution
- Interest = (25000 × 8 × 6) ÷100 = ₹12,000
- Amount = 25,000 + 12,000 = ₹37,000
Shortcut
- 8 × 6 = 48%
- Interest = 48% of ₹25,000 = ₹12,000
No lengthy calculation needed.
Question 34
A sum doubles itself in 16 years at Simple Interest. How many years will it take to become 3.5 times the Principal?
- A. 32 years
- B. 36 years
- C. 40 years
- D. 48 years
Correct Answer - C. 40 years
Solution
- If money doubles,
- Interest = 100%
- Time = 16 years
- To become 3.5 times
- Interest required = 250%
- Time = 16 × 2.5 = 40 years
Shortcut
- Required Time = Doubling Time × Required Interest % ÷100 = 16 × 250 ÷100 = 40 years
A sum becomes ₹19,965 after 3 years at 10% Compound Interest. Find the Compound Interest earned.
- A. ₹4,565
- B. ₹4,765
- C. ₹4,965
- D. ₹5,165
Correct Answer - C. ₹4,965
Solution
- For 10%, 3 years multiplier = 1.331
- Principal = 19,965 ÷ 1.331 = ₹15,000
- Compound Interest = 19,965 − 15,000 = ₹4,965
Shortcut
- Remember: 10%
- 3 years Multiplier = 1.331
- Directly divide the Amount by 1.331, then subtract from the Amount.
Question 36
A sum of ₹20,000 is invested at 10% Compound Interest for the first year and 20% Compound Interest for the second year. Find the Amount after 2 years.
- A. ₹26,000
- B. ₹26,200
- C. ₹26,400
- D. ₹26,500
Correct Answer - C. ₹26,400
Solution
- After 1st Year = 20,000 × 1.10 = ₹22,000
- After 2nd Year = 22,000 × 1.20 = ₹26,400
Shortcut
- When the rate changes every year,
- Multiply the growth factors directly: ₹20,000 × 1.10 × 1.20 = ₹26,400
Question 37
A sum of ₹16,000 is invested at 10% per annum, compounded half-yearly for 1 year. Find the Amount.
- A. ₹17,600
- B. ₹17,620
- C. ₹17,640
- D. ₹17,660
Correct Answer - C. ₹17,640
Solution
- Since compounding is half-yearly:
- Rate per half-year = 5%
- Number of periods = 2
- Amount = 16,000 × (1.05)² = 16,000 × 1.1025 = ₹17,640
Shortcut
Whenever "Half-Yearly" appears:
- Divide Rate by 2
- Multiply Time by 2
Then use the normal CI formula.
Question 38 (Reverse Principal)
The Compound Interest earned in 2 years at 10% is ₹2,520. Find the Principal.
- A. ₹10,000
- B. ₹11,000
- C. ₹12,000
- D. ₹13,000
Correct Answer - C. ₹12,000
Solution
- For 10% CI in 2 years,
- Multiplier = 1.21
- Amount = Principal + CI
- If Principal = ₹12,000
- Amount = 12,000 × 1.21 = ₹14,520
- CI = ₹14,520 − ₹12,000 = ₹2,520
- Hence, Principal = ₹12,000
Shortcut
Remember common CI values:
- ₹10,000 → CI = ₹2,100
- ₹12,000 → CI = ₹2,520
- ₹20,000 → CI = ₹4,200
Question 39 (Simple Interest)
A person borrowed ₹18,000 at 15% Simple Interest for 5 years. Find the total Amount payable.
- A. ₹30,500
- B. ₹31,000
- C. ₹31,500
- D. ₹32,000
Correct Answer: B. ₹31,500
Solution
- Interest = (18,000 × 15 × 5) ÷ 100 = ₹13,500
- Amount = ₹18,000 + ₹13,500 = ₹31,500
Note: The options above contain a numbering typo. The mathematically correct amount is ₹31,500, which corresponds to Option C, not B.
Shortcut
- 15 × 5 = 75%
- Interest = 75% of ₹18,000 = ₹13,500
Question 40
A sum becomes ₹26,620 after 2 years at 10% Compound Interest. Find the Principal.
- A. ₹20,000
- B. ₹21,000
- C. ₹22,000
- D. ₹23,000
Correct Answer - C. ₹22,000
Solution
- Multiplier for 10% (2 years) = 1.21
- Principal = 26,620 ÷ 1.21 = ₹22,000
Shortcut
- Whenever the rate is 10% for 2 years:
- Simply divide the Amount by 1.21.
- No long calculation is required.
AFCAT Master Shortcut Sheet
Common CI Multipliers
| Rate | 1 Year | 2 Years | 3 Years |
|---|---|---|---|
| 5% | 1.05 | 1.1025 | 1.157625 |
| 10% | 1.10 | 1.21 | 1.331 |
| 12% | 1.12 | 1.2544 | 1.404928 |
| 15% | 1.15 | 1.3225 | 1.520875 |
| 20% | 1.20 | 1.44 | 1.728 |
| 25% | 1.25 | 1.5625 | 1.953125 |
Exam Tricks
Trick 1
- If the rate changes every year: Multiply the yearly growth factors.
- Example: 10% then 20% = ×1.10 ×1.20
Trick 2
Half-Yearly Compounding
- Rate ÷ 2
- Time × 2
Trick 3
Quarterly Compounding
- Rate ÷ 4
- Time × 4
Trick 4
For SI
- If you know: Principal, Interest
- Then, Interest % = (Interest ÷ Principal) × 100
- Finally, Rate = Interest % ÷ Time
Question 41
A sum of ₹18,000 is invested at 15% Compound Interest for 2 years. Find the Compound Interest earned.
- A. ₹5,400
- B. ₹5,805
- C. ₹6,000
- D. ₹6,210
Correct Answer - B. ₹5,805
Solution
- Amount = 18,000 × (1.15)² = 18,000 × 1.3225 = ₹23,805
- Compound Interest = 23,805 − 18,000 = ₹5,805
Shortcut
- For 15% and 2 years, remember: Multiplier = 1.3225
Question 42 (Reverse Principal)
A sum becomes ₹31,250 after 2 years at 25% Compound Interest. Find the Principal.
- A. ₹19,000
- B. ₹20,000
- C. ₹21,000
- D. ₹22,000
Correct Answer - B. ₹20,000
Solution
- Multiplier (25%, 2 years) = 1.5625
- Principal = 31,250 ÷ 1.5625 = ₹20,000
Shortcut
- Remember: 25% for 2 years = 1.5625
Question 43 (Simple Interest)
At what rate of Simple Interest will ₹24,000 become ₹31,200 in 6 years?
- A. 4%
- B. 5%
- C. 6%
- D. 7%
Correct Answer - B. 5%
Solution
- Interest = ₹31,200 − ₹24,000 = ₹7,200
- Rate = (7,200 × 100) ÷ (24,000 × 6) = 5%
Shortcut
- Interest = ₹7,200
- Percentage = 7,200 ÷ 24,000 × 100 = 30%
- Rate = 30 ÷ 6 = 5%
Question 44
The difference between Compound Interest and Simple Interest for 2 years at 20% per annum is ₹480. Find the Principal.
- A. ₹10,000
- B. ₹11,000
- C. ₹12,000
- D. ₹13,000
Correct Answer: C. ₹12,000
Solution
Formula: Difference = P × R² ÷ 10000
- 480 = P × 400 ÷ 10000
- 480 = P ÷ 25
- P = 480 × 25 = ₹12,000
Shortcut
- At 20%, Difference = 4% of Principal
- So, Principal = 480 × 25 = ₹12,000
Question 45
A person borrowed ₹40,000 at 12% Simple Interest for 3 years. Find the total Amount payable.
- A. ₹53,600
- B. ₹54,000
- C. ₹54,400
- D. ₹55,000
Correct Answer - C. ₹54,400
Solution
- Simple Interest = (40,000 × 12 × 3) ÷ 100 = ₹14,400
- Amount = ₹40,000 + ₹14,400 = ₹54,400
Shortcut
- 12 × 3 = 36%
- Interest = 36% of ₹40,000 = ₹14,400
- Amount = ₹54,400
Question 46 (Compound Interest)
A sum of ₹25,000 is invested at 12% Compound Interest for 2 years. Find the Amount.
- A. ₹30,860
- B. ₹31,160
- C. ₹31,360
- D. ₹31,560
Correct Answer - C. ₹31,360
Solution
- Multiplier (12%, 2 years) = (1.12)² = 1.2544
- Amount = 25,000 × 1.2544 = ₹31,360
Shortcut
- Remember: 12% for 2 years → 1.2544
- No need to apply the complete formula every time.
Question 47 (Simple Interest)
At what rate of Simple Interest will ₹18,000 become ₹22,500 in 5 years?
- A. 4%
- B. 5%
- C. 6%
- D. 7%
Correct Answer- B. 5%
Solution
- Interest = 22,500 − 18,000 = ₹4,500
- Rate = (4500 ×100)/(18000 ×5) = 5%
Shortcut
- Interest % = 4500 ÷18000 ×100 =25%
- Rate =25÷5 = 5%
Question 48 (Difference Between SI & CI)
The difference between Compound Interest and Simple Interest on a sum for 2 years at 15% is ₹675. Find the Principal.
- A. ₹25,000
- B. ₹28,000
- C. ₹30,000
- D. ₹32,000
Correct Answer - C. ₹30,000
Solution
- Formula: CI − SI= (P ×15²)/10000
- 675 = P ×225/10000
- P = (675 ×10000)/225 = ₹30,000
Shortcut
- At 15% Difference = 2.25% of Principal
- Principal =675÷2.25% =₹30,000
Question 49
A sum becomes ₹18,150 after 2 years at 10% Compound Interest. Find the Compound Interest earned.
- A. ₹2,850
- B. ₹3,000
- C. ₹3,150
- D. ₹3,300
Correct Answer: C. ₹3,150
Solution
- Principal =18,150÷1.21 =₹15,000
- Compound Interest =18,150−15,000 = ₹3,150
Shortcut
- Whenever you see 10% + 2 Years
- Immediately think Multiplier =1.21
Question 50
A person borrowed ₹50,000 at 8% Simple Interest for 5 years. Find the total Amount payable.
- A. ₹68,000
- B. ₹69,000
- C. ₹70,000
- D. ₹71,000
Correct Answer - C. ₹70,000
Solution
- Simple Interest =(50,000 ×8 ×5)/100 =₹20,000
- Amount =50,000+20,000 = ₹70,000
Shortcut
- 8 ×5 =40%
- Interest =40% of ₹50,000 =₹20,000
- Amount =₹70,000
Common Mistakes Students Make
- Confusing Amount with Interest.
- Forgetting to subtract the Principal in CI questions.
- Using the SI formula in Compound Interest questions.
- Ignoring whether compounding is yearly, half-yearly, or quarterly.
- Not memorizing standard CI multipliers.